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I Need a Brain teaser for College Credits for Algebre

OSU_Buckguy;2058566; said:
my guess is that there is an infinite number of multiples of 6 and 7. need to get my calculator out for that one, though.

Point taken. "within a reasonable range for a human lifespan" was of course meant to be understood. But the goose and the gander, and all that, so I've been goosed.
 
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OSU_Buckguy;2058575; said:
so says the mortal one.

Are you considering a change of avatar?

258963569_9a76acec88.jpg
 
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BB73;2058563; said:
I guessed 84, since there aren't that many multiples of both 6 and 7. 42 is too young to fit and 126 would make him the world's oldest person, and neither of those is also divisible by 12.

It fit the answer, and was easier than constructing the equation. So unless somebody has to show their work, I wouldn't use that question.

Pffft. Always have to show your work, old man.

X= age of son at death
Y = age of father at death
Z = age of father when son was born

2X = Y ---> Y/2 = X
Y-X-4 = Z
Y/6 + Y/12 + Y/7 + 5 = Z

Substitution:
Y - Y/2 - 4 = Y/6 + T/12 + Y/7 + 5

Combining:
Y/2 - 4 = 14Y/84 + 7Y/84 + 12Y/84 + 5

Y/2 - 4 = 33Y/84 + 5
Y/2 = 33Y/84 + 9
42Y/84 = 33Y/84 + 9
9Y/84 = 9
9Y = 756
Y = 84

Now don't you feel so much better knowing that your answer was correct?
 
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Bucky Katt;2058608; said:
Pffft. Always have to show your work, old man.

X= age of son at death
Y = age of father at death
Z = age of father when son was born

2X = Y ---> Y/2 = X
Y-X-4 = Z
Y/6 + Y/12 + Y/7 + 5 = Z

Substitution:
Y - Y/2 - 4 = Y/6 + T/12 + Y/7 + 5

Combining:
Y/2 - 4 = 14Y/84 + 7Y/84 + 12Y/84 + 5

Y/2 - 4 = 33Y/84 + 5
Y/2 = 33Y/84 + 9
42Y/84 = 33Y/84 + 9
9Y/84 = 9
9Y = 756
Y = 84

Now don't you feel so much better knowing that your answer was correct?

I knew my answer was correct - I plugged in 84 and went through the stuff to verify it. It was a lot faster.

But now I believe that you didn't cheat your way through to that bean-counting degree. At least not in Algebra class.
 
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1AkronBuck;2058395; said:
The question...It was asked on this site a few years back If any one remembers ........


If any one can help me...

The Teaser/ question goes something like this....


A person goes shopping and each time they enter a store they spend half the amount they spent at the previous store ...How much did they spend ..


If anyone remembers.... HELP....

Ok, here's the skinny. It's an exponential decay situation, but it lacks information-there needs to be an amount somewhere. How much did you start with, end with, have at store five, et cetera.
 
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